Friends, let's see if I understood correctly.
This means the internal diode between pins 1 and 2 starts conducting at 1.2-1.4V. The ideal input current value is 20mA. The pulses coming out of the bridge rectifier are 17V. So, the resistance I need to add before the bridge rectifier is:
R3 = R4 = (17 - 1.2) / 0.02 = 790 ohms
About the output:
This means that unless VCE reaches BVCEO (35 V), there is no output signal? I can hardly believe I understood this correctly.
If I wish to receive the output signal in a digital pin of my Netduino/Arduino MC
I guess I need to apply 5V between the collector and emitter and a 1K resistor should pull-down the current to 5mA, well within the range of the MC.
Taking these maximum ratings into account:
the 5mA from the mains of the MC + the transferred current must be below 50mA, right?
Some other unclear detail: between which points is this reading taken:
Out and Main GND of the MC?
or Out and Digital GND of the MC?
Thanks, my friends