Let’s assume we have the following schematic :

In this schematic we have a charged capacitor and a coil (diodes are here only to make a one way road for electrons)

Our goal in this circuit is to discharge the capacitor in the coil and show that there is more energy at the end of the operation.

Ok let’s go !

For our purposes we will use for example the following datas for the capacitor and the coil.

C1 = 100uF

L1 = 122mH

R1 = 10 Ohms

Capacitor C1 is charged to 2000V.

R1 is the resistance of the coil

Ok here we go :

So let’s compute the total energy stored in the capacitor :

Now i close the switch « S1 », electrons are flowing trough the coil L1.

Now we will compute the energy stored in the coil :

Ok but was is the value of « I » (current) ?

So let’s compute the total energy in the coil when i close the switch :

Finally :

So, we can clearly see that there is more energy when the coil receive the voltage from our capacitor ! When you close the switch we make a strong short-circuit. All energy is then stored into the coil into the electro-magnetic form until it vanish when all electrons have passed and returned into the capacitor.

In this example i do not make an explanation on « how to retrieve this excess of energy » but just show that using theses basic equations we can "produce more energy".

Best results are with theses parameters :

Capacitor C1 must be the smaller as possible and with the highest voltage as possible.

Coil L1 must be the bigger as possible with the lowest resistance as possible