The Input Coil

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Chris posted this 14 July 2018

My Friends,

In DC Switched Machines, the Input Coil plays a very important role.

Two things are achieved:

  1. Creates a Magnetic Field in the Device.
  2. Induces an E.M.F, or a Voltage on the terminals of the Output Coils.

 

There is another way to think about this, the Magnetic A Vector Potential is an Electric Field with Curl:

 

 

One could say that it is the Magnetic A Vector Potential that is disturbed:

When you find the AB effect is indeed invoked, then you can adjust the magnitude of the E-fields produced in the A-potential reservoir by dA/dt. That means you adjust the rise time and decay time of the input pulses. Also play around with frequency (each unit has its own "sweet spot").

Ref: http://www.cheniere.org/correspondence/061603.htm

 

We have heard this many times before, but one example comes to mind:

 

I'm not allowed to give any more hints than that, except to point out that wire size and numbers of windings are also variables you must investigate rather thoroughly. They do have great effect on the COP.

Ref: http://www.cheniere.org/correspondence/061603.htm

 

If one were to do a full analysis on all the devices over the years, and all the Input Coils, one would find very few turns and normally a heavier gauge wire.

E.G:

  • Don Smith used: 4 turns of perhaps No# 12 Insulated Wire.
  • Akula used: 7 Turns of perhaps No# 18 Insulated Wire.
  • And so on...

We also see this in our detailed study of the Asynchronous Re-Gauging, which we have proven to be valid on many devices:

 

 

As you can see, the Regauge Region is very much shorter in Time than the Work Region. 

An Input coil must be able to do its job quickly and efficiently, and the Time to do its job can be calculated by using:

 

T = L / R

 

 

The Time Rate of Change is reduced by reducing the Inductance ( L ) and Resistance ( R ), shorter thicker wire means faster Rise Time. This makes your Regauge Region faster. This also means your Switching Time must be shorter, say 10% Duty Cycle. 

Note: We have seen, history has shown us many examples, one must find the optimum point where the Rise time has done enough to allow the Partnered Output Coils to do enough Work, in other words: "Generate" enough Electrical Energy, to cover losses and enough to Power a Load.

One such example of this is the tuning required in the following video:

 

By turning on the English subtitles you will get somewhat of an explanation of the Timing required.

Another example is Bradley's RT, by attaching the Fan, slowing the Rotor and the Pulses, the machine was below unity. We must invoke the Partnered Output Coils interaction so as to: 

 

Below is a bad google translation in a text file.

Related Threads:

  1. Impulse Pressure Wave

   Chris

Attached Files

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Chris posted this 22 July 2018

Hey CD,

A Coil with 3 turns may have an Inductance of say: 20nH and say: 0.02Ω of Resistance.

So, according to our formula: τ = L/R we can calculate: τ = 0.000000020 / 0.02 = 0.000001 * 5 = 0.000005 seconds.

So, in 0.000005 seconds, the Current has reached Maximum value.

Similarly, τ = 0.16H / 0.8Ω = 0.2 * 5 = 1 seconds to build to maximum Current.

Remember, the faster the Rate of Change or the Magnetic Field, the Higher the Voltage will be.

   Chris 

Chris posted this 22 December 2018

My Friends,

The Input Coil is the start of an Avalanche Effect. But, the Input Coil is not the Source of access to the power of the Universe! It is only the catalyst.

At this stage, to be honest, all else is irrelevant, as our Two Partnered Output Coils MUST, React and Counter-React with each other.

One must be Opposite to the other according to Faradays Law of Electromagnetic Induction, this being observed as Lenz's Law! The Potential gained on the Terminals of the Coil and the Timed response of Drawing Current, at the same time as the opposite Coil being equal and opposite in the Potential domain, creates this:

 

The Linear decrease in Amplitude of the Potentials to Zero:

 

This response has cost us only a very small amount, the small but efficient timed pulse of the Input Coil to bring up the Potentials, is the first Action.

We have:

Action, Reaction and Counter-Reaction.

 

So, the actual effect, Bucking Coils, is a critical objective, without it, we are just playing with Magnetic Fields. Something that those before us did also, until observing the key principles of Energy "Generation", being that of which is described above.

We have the opportunity to circumvent much of the random chance experiments, and have the specific, goal orientated conditions, for a working Energy Machine!

Of course efficiency is dependant on Magnetic Resonance which is specifically related to Antenna Theory, thought of in the following way:

Space has quiet zones through which energy glides virtually unreflected. There are also noisy zones where energy current becomes incoherent, bounces about and splits apart. Noisy zones in space have either rapidly changing geometry or rapidly changing impedance sqrt( μ / ε )

 

All it means is the Traversing of Current down the Coils with least possible Impedance.

The goal, the specific, required focus, is in the Bucking Coils, Partnered Output Coils.

   Chris

Chris posted this 03 September 2019

My Friends,

We need to start thinking about our Input Coil!

What is the Input Coil actually doing in our System?

In The Mr Preva Experiment, we saw the need to find the Frequency of Magnetic Resonance where the two Coils were 180 Degrees out of phase.

Now an experiment:

Lets say we found this Frequency to be 73KHz, that means we need 73,000 of these:

per second!

If we are using a DC Pulsed System, most of us seem to be going this way, then we need to only think of exactly one half of the above Blue Cycle! Our DC Pulse must be short enough in time to match this Frequency!

We can be smart about this, because we have to be:

  • At 7,300 Hertz
  • With a 10% Duty Cycle


Is the same as having Half Cycle Magnetic Resonance at 73,000 Hertz, for a DC Pulsed System.

Remember: We need the Off Time! This is seen below!

This will give us:

 

Where:

  • Top Trace is the Input.
  • Bottom Trace is the Output.

 

This means, we need to think about our Input Coil, it must be designed to be able to provide short sharp pulses efficiently. So a short length, thicker, with very low Duty Cycle.

In this Post, I posted this Image of Don Smith's Output Circuit, we all sould be familir with the Partnered Output Coils and how they work:

 

We just have to learn how to efficently bring them into Resonance!

Remember: Resonance means Maximum Amplitude for minimum Input and also the Power used will be the same if one uses a short sharp pulse over time or a long pulse over time through a higher resistance coil. The Mean power over time can be the same.

I hope this helps!

   Chris

patrick1 posted this 04 September 2019

Haha Chris, you are definitely right about needing an offtime, - my home made, linear power supplies are going crazzy with resonance, - as soon as im getting massive light, - just before and after resonance, - and when it is in the zone, - my current jumps from 100ma, too off the 5amp scale... 

hehe i am having fun, but not so much success, - i plan too focus on this mr preva experiment again,  and also i am testing delayed conduction methods with inline series MOV's and  mix'n'match diode juntions, with a back2back 12v zener and 1000v 10a10      ....      recently. my wave modulation attempts at making everything variable have not been so successful despite the complexity, - some of my best work ever, for sure, but i think this is a sign of me actaully starting too figure out what too aim for.

this is why my posts have been slow lately, - i don't want too look like im running out of puff, -but this approach is not so conducive of lots of experimentation

Chris posted this 05 January 2020

My Friends,

Those that are busy replication Asymmetrical Regauging, Please, lets bring some insight to this thread: The Input Coil.

   Chris

Chris posted this 03 February 2020

My Friends,

Just a friendly reminder, the Input Coil, the Frequency and Duty Cycle is important:

 

The input, how you drive your Partnered Output Coils is a bit of an Art-form in itself.

Best Wishes,

   Chris

Chris posted this 08 February 2020

Hey CD,

I have not checked the math, but from what I see, it looks good!

Methods of increasing efficiency, increasing Amplitude of V and I without adversely affecting the Input. Using resonance is the best way forward. Because Amplitude is maximum when XC and XL are equal, which is Resonance, where XC and XL cancel and Impedance becomes only the DC Resistance of the Coils.

Remember what Floyd Sweet said:

Resonance frequencies may be maintained quite constant at high power levels so long as the load remains constant. We are all familiar with AM and FM propagation, where in the case as AM, the voltage amplitude varies, and with FM, the frequency is modulated.

However, the output power sees a constant load impedance, that of the matched antenna system. If this changes, the input to the antenna is mismatched, and standing waves are generated resulting in a loss of power.

Ref: Magnetic Resonance - By Floyd A. Sweet. Ph.D.

 

We need to avoid the loss of Power, so Resonance is required! Or at least close to it!

I hope this helps! Your'e on the right track, have been for a long time now!

It is just a case of working to get the best Output to Input now!

   Chris

 

P.S: One microsecond is 1e-6 seconds? 250,000?

 

NOTE: Re-reading, this is confusing, a frequency of 5Khz with a Duty Cycle of 4μs is not the same as 250Khz. 5Khz @ 2% Duty Cycle gives an On-Time of 4μs approx. Your Input Coil has a Rise Time, the advantage is in the Rise time. The Rise Time needs to match your 4μs for an optimum switch.

Vidura posted this 09 February 2020

Hey Friends, If we have a quarter wave time of 4us, this means the period of resonance is 16us. If we use a lower harmonic of this frequency it has to be in phase with the fundamental resonant frequency. The puls duration should be constant at 4us, and the off time has to been chosen such that the next puls matches with the rising sine wave at zero crossing. For example the time between the rising edge of consecutive pulses have to be always multiples of 16us for this coil frequency. Vidura.

Chris posted this 18 September 2020

My Friends,

The Input Coil is a very important aspect to monitor!

I am showing this, under no Load Conditions, this is a simple Core, Coil and High Side Mosfet Switch, a similar circuit to this:

 

Where: R1 is the Input Coil instead.

We have covered before, the fact that the Input Coil sends Power Back to your Input! This is directly related to the Argand Diagram:

 

We can have Positive Voltage and Positive Current for Positive Power!

Inversely, we can have Positive Voltage and Negative Current, for Negative Power!

Here is an example:

 

Where:

  • Purple Trace is the Math, showing Positive and Negative Power.
  • Pink Trace is the Gate Signal to the Mosfet.
  • Yellow is the Input Voltage.
  • Teal Trace is the Input Current, both Positive and Negative.

 

I must apologise, I have better examples of this, but do not wish to confuse everyone. This example is sufficient to show what I am talking about.

 

Again, marked in Red, Positive Voltage and Negative Current, you have Negative Power. Not Negative Energy, Negative Power, I hope people do not confuse this as I believe people have in the past.

I hope this helps others when doing experiments, knowing what to look for is very important!

Remember: This is the very reason you can NOT Use RMS Measurements on the Input! See Measurements Thread and see the above Figures:

  • Average: 95.7 mW
  • RMS: 1.28 W


A Huge error here! 1.28 - 0.095 = 1.185 Watts. 13.474 times!

RMS is totally Wrong! Remember, your Zero Graticule Line is very important:

  • above: Positive
  • below: Negative

 

Its worth noting, there is 1.28 Watts in the System. An analogy, inaccurate as it stands, is, Power Delivered to the Coil might be in the order of 1.28 Watts. Then the Coil returns 1.28 - 0.095 = 1.185 Watts back to the Power Supply. So the Total Power used is only: 0.095 Watts. Power Returned, is not Power Used! 

 

This is Reactive Power Conditions, except V and I are in apparent phase. We have 1.28 Watts of Work Done for the Cost of 0.095 Watts. I hope this makes sense? Please understand, the example is not giving accurate Power In and Out, only using figure seen in this Analogy for simplicity.

I believe, 1.28 - 0.095 / 2 = 0.5925, is the In and Out power. I am sure others here, perhaps YoElMiCrO, Jagau, Vidura, or someone can correct me here?

Meaning, the Power in Purple Above the Zero Graticule Line:

 

Is more than the Math in Purple Below the Zero Graticule line:

 

By: 0.095 Watts.

My Friends, if I have anything wrong here, please ensure you correct me.

Best wishes, stay safe and well My Friends,

   Chris

Atti posted this 28 September 2020

Note: We have seen, history has shown us many examples, one must find the optimum point where the Rise time has done enough to allow the Partnered Output Coils to do enough Work, in other words: "Generate" enough Electrical Energy, to cover losses and enough to Power a Load.

 

You're absolutely right. I think we really need to pay more attention to the input coil. Although apparently it is barren energy. But don't be fooled. A picture of the current.

Atti

Chris posted this 28 September 2020

Hey Atti,

Well done my Friend! Yes, you are right! So many, over look the simplest things on the other forums! We investigate all things no matter how big or small! That's why we are so very far ahead of the other forums!

All Current below the Zero Graticule Line is Current returning to the Power Supply! This makes for a greatly reduced Input Power!

Best wishes, stay safe and well My Friend,

   Chris

Atti posted this 27 November 2020

Sequel. Looking at the L1 input coil.

Melendor posted this 21 November 2022

Hello Chris and Team.
I see in all the schematics , a diode , from the Source to drain of the Mosfet in a High side switch configuration.
What purpose does it have ?

Also if we switch the Low side of the inductor will we place the diode  between the Drain and the Negative side of the Inductor ?

I really trying to find more information about it.
Thank you very much guys.
~~~Melendor the wizard.

Plasmonic posted this 21 November 2022

Hi Melendor,

As far as my understanding of the input diode purpose is it can serve to bypass the rather slow and wasteful diode that is part of the mosfet design.

If you have current coming back to the source it should pass through a dedicated fast diode easier than it would the mosfet body diode.

Matt

Chris posted this 22 November 2022

My Friends,

@Melendor:

Plasmonic is absolutely correct! To reduce Stress on the Mosfet, and allow for High Currents to go back to the Source, E.G: Your Battery or PSU, Bench top Power Supply, this Diode serves as a easy path way for Reverse Current:

Hi Melendor,

As far as my understanding of the input diode purpose is it can serve to bypass the rather slow and wasteful diode that is part of the mosfet design.

If you have current coming back to the source it should pass through a dedicated fast diode easier than it would the mosfet body diode.

Matt

 

Here, we see this reverse Current:

 

Where:

  • Purple Trace is the Math, showing Positive and Negative Power.
  • Pink Trace is the Gate Signal to the Mosfet.
  • Yellow is the Input Voltage.
  • Teal Trace is the Input Current, both Positive and Negative.

 

Of course, this is already shown above and explained, however, the DC Power Supply can not supply Negative Current, and because the Tension of the Voltage is higher after Mosfet Off, we have Current Flow Backwards through the Circuit!

 

Again, marked in Red, Positive Voltage and Negative Current, you have Negative Power. Not Negative Energy, Negative Power, I hope people do not confuse this as I believe people have in the past.

I hope this helps others when doing experiments, knowing what to look for is very important!

Remember: This is the very reason you can NOT Use RMS Measurements on the Input! See Measurements Thread and see the above Figures:

  • Average: 95.7 mW
  • RMS: 1.28 W


A Huge error here! 1.28 - 0.095 = 1.185 Watts. 13.474 times!

RMS is totally Wrong! Remember, your Zero Graticule Line is very important:

  • above: Positive
  • below: Negative

 

Always have in your mind, a DC Power Source is incapable of Negative Current like we see!

Here is another example:

Yes, I am still seeing a very large Negative Spike:

 

About 7 Kilowatts Peak Power.

 

 

This is Negative Power: Positive Voltage x Negative Current = Negative Watts!

Mathematically, this is simple to prove: 1 x -1 = -1, there is nothing hard here.

 

Best Wishes,

   Chris

ISLab posted this 02 January 2023

Hi Chris and others,

When winding coils with multiple layers on top of a ferrite core, the inside layers will have higher impedance due to proximity of the core, and the outermost layers will have much lower impedance. In such a case, would it be better to inject the electron flow current from inside outwards or from outside in inwards for maxium field opposition between POC?

Would you please share your experience in this?

Thank you!

Chris posted this 02 January 2023

Hello ISLab,

Under ideal working conditions, the Coils Impedance becomes the DC Resistance.

This I have covered and given experiment to prove this in the Thread: Reduced Impedance Effect.

You will be able to prove this to yourself once you get your Experiment working properly.

Best Wishes,

   Chris

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ISLab posted this 02 January 2023

This I have covered and given experiment to prove this in the Thread: Reduced Impedance Effect.

You will be able to prove this to yourself once you get your Experiment working properly.

Yes, I believe that I've detected this effect. But I did not pursue more rigorous testing or validation as it seemed like a distraction from the immediate focus.

This whole phenomenon is totally unknown to current science (or rather kept secret by the Cabal elite). Your site is the only place I know of that covers this! But one day, I hope, it will be part of every textbook.

 

Under ideal working conditions, the Coils Impedance becomes the DC Resistance.

Does that mean we should not worry about which direction to layer the coils?

But in the initial phase of tuning, when still outside resonance and hence under non-ideal conditions, should we try to optimise this in our coils in any case?

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Chris posted this 02 January 2023

Hello ISLab,

Re:

Does that mean we should not worry about which direction to layer the coils?

But in the initial phase of tuning, when still outside resonance and hence under non-ideal conditions, should we try to optimise this in our coils in any case?

 

A simple experiment I have shared: Some Coils Buck and Some Coils DONT will give you a little more information on this topic. Simple experiments yield answers.

YES, on your thread, get your Magnetic Fields: both B and H up and Output increases proportionally.

Best Wishes,

   Chris

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