Donovan's experiments and learning.

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  • Last Post 26 February 2023
donovan posted this 25 December 2022

Hi,

Merry Christmas!

Here is what I have tried, am I headed in the right direction?

I think the most important thing in this experiment, is set up like this, when I disconnect the Bucking Coil Diode, the light goes to about 1/10 brightness.

I just built this with stuff laying around.

Things to try next for improvement:

1)  My signal generator won't put out a low duty cycle, so I just built one up real quick from a TL494, which seems to not be able to go to the lower frequencies.  Right now the scope shots are at .2ms/div, About 1kHz.  I would like to try lower frequencies.

2) Try different loads, maybe lamps in series to get the voltage up, with a higher resistance load.

3) Try Zener diodes, or Zener diode and MOSFET's on the bucking coil to get voltages up.

4) Maybe try smaller coils to learn more from.

Transformer

Transformer

Input Voltage (top), and Input current

Input Voltage, Top, and input current

Input Voltage (top), and Lamp current

Input Voltage, top, and Lamp current

Transformer and Lamp Circuit

The Test setup

Input Voltage (top), and Buck Diode current

Input Voltage, Top, and Bucking Diode Current.

Any input is appreciated!

 

Donovan

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Chris posted this 23 February 2023

Hey Donovan,

Yes, this:

 

Is very good! You have all the indicators that your heading in the right direction! This is by far the best you have produced so far!

We see Positive Voltage, and also a Negative Current starting to become more predominant on your Input Traces! This is super important!

Your Output is looking good! A bit Curvy but hey its a Plus to have Amplitude on each Trace! Perhaps there is a bit of Capacitance on the Load? I use a Linear Resistance, as a Load. 

PLEASE: I urge you to study this in more detail, understand this fully, study the Input Pulse, Duty and Amplitude, and you will gain a knowledge where it wont be long before you're powering your House from your Energy Machine!

Best Wishes,

   Chris

donovan posted this 24 February 2023

Hi,

Thanks for the feedback, Chris.

The last little while, I have been tuning to get some power output, but never really saw the wave forms like yours.  I was thinking for a while, I am just building really efficient SMPS's.  And I keep thinking about the POC's bucking each other, and never really saw anything that made sense to me.  Then I thought, lets tune and see if I can get a waveform, and not worry so much about power out.  And this is where I ended up.

So, your thoughts on my next statement?  I studied these wave forms for a long time.

"In the photo above I think the most important aspect (that I need to concentrate on) in the POC theory, is the 20 us right after the Low Side MOSFET Driver turns on.  We see a steep rise time in the input current.  We see similar rise times in L2 and L3 currents.  If these current ramps continued for the entire duty cycle, it would probably do wonders."

Donovan

Chris posted this 24 February 2023

Hi Donovan,

I would disagree, this image is almost exactly like my waveforms:

 

and your waveforms here, indicate Power on the Outputs, plural. Anything above or below the Zero Graticule Line is Power, or at least a Potential.

 

So, I think you now need to think about where this power is coming from, its not the Input Coil is it?

What is your Input Coil doing to your POC?

Best Wishes,

   Chris

Chris posted this 25 February 2023

My Friends,

By carefullt studding the Waveforms Donovan has shared, we can see something quite remarkable:

 

I asked the question:

What is your Input Coil doing to your POC?

 

So: What is your Input Coil doing to your POC?

Can you see something remarkable like I can? Can you see a Coil, POCX doing something quite amazing?

 

What is occurring here? What is the Potential doing on the Traces? Why does the Blue and Pink Trace go negative very fast? Below the Zero Graticule Line!

What's the Slope on the Traces I have Pointed out? Why is that there? We have spoken of: Rise over Run now for a long time. So what's this Slope that has a Rise and a Run?

Best Wishes,

   Chris

donovan posted this 25 February 2023

Hi,

I haven't done much in the lab the last couple days......busy cleaning up the garage before the farming season starts, and I would rather be outside!!!

And I have been thinking about what the next step should be.

I have been studying these last couple scope shots, though.

I believe......those 10-15 microseconds of trace that you pointed out.......that is what we are after........this is when the POC are actually creating their two opposing fields that are bucking.......they are in resonance......they are opposing......the net circuit impedance is minimum.......currents are maximum.......rise times are at their peak.......I need more of this.

To take it one more step......I need POC L2, the blue trace to have more stored energy at that instant, to continue the bucking for a longer time period.....When the blue trace runs out of steam, and goes to zero (flat line), that is the end of the actual bucking action.....

Any feedback is welcome.

Donovan

Chris posted this 25 February 2023

Hey Donovan,

You say:

Any feedback is welcome.

 

All your answers lay here, on this forum! 

We have covered everything right here! Every Detail you need to move to the next step! Its all in:

 Start Here → Builders Guide to Aboveunity Machines

 

So, at the moment, your next step is; Study the waveform further, find out why you see the Rise over Run, the Slope or Gradient, and why the Blue and Pink Traces drop Negative so fast!

Yes, you are correct:

more stored energy at that instant, to continue the bucking for a longer time period

 

The total Bucking Force, the Stored Energy of Each Opposing Field is dependant on what?

The Magnetic Field: 1/2 LI2

  • Turns N
  • Current I
  • Inductance, which is derived by the Turns and Current: L = VL /  Δi / Δt

 

Where: L is the inductance in Henries, VL is the voltage across the coil and Δi / Δt is the rate of change of current in Amperes per second, A/s.

and Current I is dependant on what: I = V / R

  • Voltage V
  • Resistance R

 

and what is Voltage dependant on: ΔΦB / Δt

  • The Time Rate of Change ( Δx / Δt ) of the Magnetic Field B ( ΦB )
  • Turns N
  • Cross Sectional Area CSA

 

Do you see a Loop here that one step follows the other?

The Other Forums have no idea!

We are Light Years Ahead of the Other Forums!

Best Wishes,

   Chris

donovan posted this 26 February 2023

Hi,

Thanks!

Donovan

Chris posted this 26 February 2023

Hey Donovan,

When I said:

and what is Voltage dependant on: ΔΦB / Δt

  • The Time Rate of Change ( Δx / Δt  of the Magnetic Field B ( ΦB 
  • Turns N
  • Cross Sectional Area CSA

 

You realise this is the very same ΦB of the opposite Partnered Output Coil? Thus the Loop of Feed Forward and Feed Back occurring?

The Magnetic Field: 1/2 LI2

  • Turns N
  • Current I
  • Inductance, which is derived by the Turns and Current: L = VL /  Δi / Δt

 

Where: L is the inductance in Henries, VL is the voltage across the coil and Δi / Δt is the rate of change of current in Amperes per second, A/s.

and Current I is dependant on what: I = V / R

  • Voltage V
  • Resistance R

 

and what is Voltage dependant on: ΔΦB / Δt

  • The Time Rate of Change ( Δx / Δt  ) of the Magnetic Field B ( ΦB  )
  • Turns N
  • Cross Sectional Area CSA

 

 

Initially, this can be some what 'difficult' to wrap ones head around, because its not taught, its not accepted by any institution or authority, due to ignorance and stupidity, but right there on the bench, you have exactly this occurring, if you study this and take advantage of the Resonant 'loop'.

Your Input Coil see's no Negative Forces! It becomes free, only to regulate the Frequency at which your Partnered Output Coils Operate.

Best Wishes,

   Chris

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